tan²theta + 3 = 3sectheta , find theta
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Answer:
tan2 ø - 3 sec ø +3 =0
for tan2 ø =sec2 ø -1
sec2ø -1 -3 secø + 3 =0
sec2ø-3 sec ø + 2 =0
sec2ø-2 sec ø -1 sec ø+ 2 =0
sec ø(sec ø -2) -1 (sec ø -2) =0
(sec ø -2)(sec ø -1) =0
sec ø = 2 or sec ø = 1
ø = sec-1 (2) or ø = sec-1 (1)
ø = 60 or ø =0
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