Question

tan²theta - sin² = tan²theta×sin²theta
Prove it.​

Answer 1

Answer:

L.H.S= tan^2theta - sin^2theta = sin^2theta/cos^2theta - sin^2 theta =

sin^2 theta (1/cos^2theta - 1) {taking common sin^2theta}

=sin^2theta (1-cos^2theta)/cos^2theta =sin^2theta × (sin^2theta/cos^2theta)=(sin^2theta )×( tan^2 theta )=R.H.S

Hence, proved......

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Answer 2

Answer:

to prove tan^2°-sin^2°=tan^2°*sin^2

Step-by-step explanation:

lhs

tan^2°-sin^2

sin^2° -sin^2°

cos^2°

sin^2°-sin^2°*cos^2°

cos^2°

sin^2°(1-cos^2°)

cos^2°

sin^2°*sin^2°

cos^2°

sin^4°

cos^2°

rhs

tan^2°*sin^2°

sin^2°*sin^2°

cos^2°

sin^4°

cos^2°

lhs=rhs

thus it is proved