Math, asked by 778993syaswanthkumar, 18 days ago

tan²theta+tan⁴theta=sec⁴theta-sec²theta​

Answers

Answered by sandy1816
0

 {tan}^{2}  \theta +  {tan}^{4}  \theta \\  \\  =  {tan}^{2}  \theta(1 +  {tan}^{2}  \theta) \\  \\  =  {tan}^{2}  \theta  {sec}^{2}  \theta \\  \\  = ( {sec}^{2}  \theta - 1) {sec}^{2}  \theta \\  \\  =  {sec}^{4}  \theta -  {sec}^{2}  \theta

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