Question

tan²x - 4secx + 5=0 find general solution​

Answer 1

We have to find x given that : tan^2 x - 4sec x + 5 = 0

(tan x)^2 - 4sec x + 5 = 0

=> ( 1 - (cos x)^2)/( cos x)^2) - 4/ cos x + 5 = 0

let cos x = y

=> (1 - y^2)/y^2 - 4/y + 5 = 0

=> (1 - y^2) - 4y + 5y^2 = 0

=> 4y^2 - 4y - 1 = 0

=> (2y - 1)^2 = 0

=> 2y = 1

=> y = 1/2

=> cos x = 1/2

=> x = arc cos (1/2)

x = pi/3 + 2*pi

The angle x = pi/3 + 2*pi

$bts \: exo$

Answer 2

Question

tan²x - 4secx + 5=0 find general solution

Solutions

We have to find x given that : tan^2 x - 4sec x + 5 = 0

**************************************************

(tan x)^2 - 4sec x + 5 = 0

=> ( 1 - (cos x)^2)/( cos x)^2) - 4/ cos x + 5 = 0

Given:-

let cos x = y

(1 - y^2)/y^2 - 4/y + 5 = 0

(1 - y^2) - 4y + 5y^2 = 0

4y^2 - 4y - 1 = 0

(2y - 1)^2 = 0

2y = 1

y = 1/2

cos x = 1/2

Now:-

x = arc cos (1/2)

x = pi/3 + 2*pi

Answer

The angle x = pi/3 + 2*pi

Thanks