tan2x+sec2x=?Prove the solution
Answers
Answered by
3
Tan2x+sec2x
=sin2x/cos2x+1/cos2x
=(sin2x+1)/cos2x
=(2sinxcosx+sin^2x+cos^2x)/(cos^2x-sin^2x)
=(cosx+sinx)^2/(cosx+sinx)(cosx-sinx)
After cancellation
=(cosx+sinx)/(cosx-sinx)
=sin2x/cos2x+1/cos2x
=(sin2x+1)/cos2x
=(2sinxcosx+sin^2x+cos^2x)/(cos^2x-sin^2x)
=(cosx+sinx)^2/(cosx+sinx)(cosx-sinx)
After cancellation
=(cosx+sinx)/(cosx-sinx)
Similar questions