Question

tan²x - sin²x = tan²xsin²x​

Answer 1

Answer:

I can't understand your question can you write nicely

Answer 2

Answer:

Taking R.H.S

=Tan^2x-Sin^2x

converting all in sin and cos form

=Sin^2x/Cos^2x - Sin^2x

=(Sin^2x-Sin^2xCos^2x)/Cos^2x

=[Sin^2x(1-Cos^2x)]/Cos^2x

=[Sin^2x.Sin^2x]/Cos^2x

=Sin^2x.Tan^2x (As Sin^2x/Cos^2x=Tan^2x)

Step-by-step explanation:

Hope it's help you!!!

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