Math, asked by antasd3838, 1 year ago

Tan2x*tanx/tan2x-tanx - sinx

Answers

Answered by swaifahaque
0

Answer: sinx(2-cos^3x)/cos^3x


Step-by-step explanation:

(tan2x*tanx/tan2x-tanx)-sinx

((2tanx/1-tan^2x)/(2tanx/1-tan^2x)-tanx)  - sinx

2tanx/sec^2x  -sinx

2sinx/cos^3x -sinx

sinx(2-cos^3x)/cos^3x

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