Question

tan²xcos²x=1-cos²x please solve this

Answer 1

Solution :- tan²x * cos²x

=> sin²x/cos²x* cos²x

=> sin²x

=> (1-cos²x)

LHS= RHS proved

Used formula , tan²x = sin²x/cos²x

and , sin²x = 1-cos²x

Answer 2

Answer:

pie/6

sin^2 x = 1- cos^2 x

Step-by-step explanation:

tan^2 x cos^2 x + cos^2 x =0

cos^2 x ( 1 + tan^2 x } = 1

cos^2 x × sec^2 x = 1

1 = sin^2 x + cos^2 x

If I put x = pie/6 ,

1/4 + 3/4 = 1

1 = 1

so, value of x = pie/6