Math, asked by surajkumarbju95, 1 year ago

tan3¤-tan2¤-tan¤=tan3¤.tan2¤.tan¤ proof

Answers

Answered by ash2268

proof:
tan3a=tan(2a+a)
tan3a=tan2a+tana / 1-tan2a+tana
tan3a[1-tan2a.tana] = tan2a+tana
tan3a-tan3a.tan2a.tana=tan2a+tana
tan3a-tan2a-tana=tan3a.tan2a.tana
hence is proved.

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