Math, asked by shaurya01605, 10 months ago

Tan3 theta-1/ tan theta-1 = sec2 theta+ tan theta​

Answers

Answered by jsumanth19
1

Answer:

Step-by-step explanation:

tan3 0-1/tan0-1=sec2tan0+tan theta

(tan theta-1)(tan2 theta+tan theta+1)/tan theta-1-sec2 theta +1

tan2 theta+tan theta+1-sec2 theta+1=0

tan theta+2-1=0                                     (acco identity)

tan theta =-1

cot theta=-1

Answered by Anisha5119
3

Answer:

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