Math, asked by bradenpaul456, 8 months ago

Tan³ theta - 1 upon tan theta - 1 =sec² theta + tan theta

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Answered by sucharithaa

0

Answer:

Step-by-step explanation:To prove tan³-1/tan-1=sec²+tan²

From a³-b³=(a-b)(a²+b²+ab)

( tan-1)(tan²+1+tan)/tan-1

tan²+1+tan

From identity 1+tan²=sec² we get ans as

sec²+tan hence proved

Answered by JeetGandhi

0

Step-by-step explanation:

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