Tan³ theta - 1 upon tan theta - 1 =sec² theta + tan theta
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Step-by-step explanation:To prove tan³-1/tan-1=sec²+tan²
From a³-b³=(a-b)(a²+b²+ab)
( tan-1)(tan²+1+tan)/tan-1
tan²+1+tan
From identity 1+tan²=sec² we get ans as
sec²+tan hence proved
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Step-by-step explanation:
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