Question

Tan30 +sin60+cot45/cosec90

Answer 1

tan 30 = 1/√3

sin 60 = √3/2

cot45 =1

cosec90 =0

By putting the values ,

1/√3 + √3/2 +1 / o

i.e. answer will be not defined .

Hope it helps !!!

Answer 2

Answer:

$\frac{5\sqrt{3}}{6}+1$

Step-by-step explanation:

We have to find the value of

$\frac{\tan \left(30^{\circ \:}\right)+\sin \left(60^{\circ \:}\right)+\cot \left(45^{\circ \:}\right)}{\csc \left(90^{\circ \:}\right)}$

Now, we know that

$\csc \left(90^{\circ \:}\right)=\frac{1}{\sin \left(90^{\circ \:}\right)}$

Thus, we have

$\frac{\tan \left(30^{\circ \:}\right)+\sin \left(60^{\circ \:}\right)+\cot \left(45^{\circ \:}\right)}{\frac{1}{\sin \left(90^{\circ \:}\right)}}\\\\==\sin \left(90^{\circ \:}\right)\left(\tan \left(30^{\circ \:}\right)+\sin \left(60^{\circ \:}\right)+\cot \left(45^{\circ \:}\right)\right)$

Now, we know the values

$\sin \left(90^{\circ \:}\right)=1,\tan \left(30^{\circ \:}\right)=\frac{\sqrt{3}}{3},\sin \left(60^{\circ \:}\right)=\frac{\sqrt{3}}{2},\cot \left(45^{\circ \:}\right)=1$

Hence, we have

$1\cdot \left(\frac{\sqrt{3}}{3}+\frac{\sqrt{3}}{2}+1\right)\\\\=\frac{5\sqrt{3}}{6}+1$