tan30 +tan60 +sin90 +2+5+cos0 -sin60
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Using the values of,
tan30° = 1/√3
tan60° = √3
sin90° = 1
cos0° = 1
sin60° = √3/2
=>
tan30 + tan60 +sin 90 +7 + cos0 - sin 60
= 1/√3 + √3 + 1 + 7 +1 -√3/2
= (5+18√3)/2√3
tan30° = 1/√3
tan60° = √3
sin90° = 1
cos0° = 1
sin60° = √3/2
=>
tan30 + tan60 +sin 90 +7 + cos0 - sin 60
= 1/√3 + √3 + 1 + 7 +1 -√3/2
= (5+18√3)/2√3
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