Question

Tan30°. Tan15°. Tan75°. Tan80°=?​

Answer 1

Answer:

tan10×tan15×tan75×tan80=1

Step-by-step explanation:

Given,

tan10×tan15×tan75×tan80

Rearranging the terms, we get

=(tan10tan80)×(tan15tan75)

= [tan10tan(90-10)]×[tan15tan(90-15)]

= (tan10xcot10)×(tan15cot15)

/* We know that,

i ) tan(90-A) = cotA

ii) tanAcotA = 1 */

= 1 × 1

= 1

Therefore,

tan10×tan15×tan75×tan80=1

Answer 2

Answer:

200° is the answer 30+15+75+80=200