Question

tan315cot(-405)+cot495tan(-585)=2​

Answer 1

Step-by-step explanation:

LHS = tan315 cot(-405) + cot495 tan(-585)

= tan(90×4-45) -cot405 + cot(90×5+45) -tan585

= -tan45 . -cot(90×4+45) + (-tan45) . -tan(90×6+45)

= 1 × cot45 + 1 × tan45

= 1×1 + 1×1

= 1+1

= 2

= RHS