tan35/cot55+cot78/tan12
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Answered by
100
(tan 35°/cot 55°)+(cot 78°/tan 12°)
[tan (90°-55°)/cot 55°] + [cot (90°-12°)/tan 12°]
=(cot 55°/cot 55°) + (tan 12°/tan 12°)
=1+1
=2.
[tan (90°-55°)/cot 55°] + [cot (90°-12°)/tan 12°]
=(cot 55°/cot 55°) + (tan 12°/tan 12°)
=1+1
=2.
Answered by
32
Answer is 2.
Solution is enclosed.
Solution is enclosed.
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