tan35°+tan10°+tan35°tan10°=1
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tan ( a + b= =tan a + tan b / 1 - tan a . tanb
tan35 + tan10 =tan (35+10)× (1- tanAtanB)
so 1× ( 1 - tan35×tan10) + tan35×tan10 =1
so lhs =rhs
tan35 + tan10 =tan (35+10)× (1- tanAtanB)
so 1× ( 1 - tan35×tan10) + tan35×tan10 =1
so lhs =rhs
pilu4:
its not clear to understand...pls solve it clearly
,which step
3rd step
just put value of tan 35 + tan 10 in the equation
tan45 =1
u got it ?
not clearly....pls help
which step u can't understand
yes finally i got it thanks for help....
ok
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Answer:
Find the area of an isosceles right triangle whose hypotenuse is .18cm
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