Math, asked by mktmanagerspc, 1 year ago

tan3a-1/tan a-1=sec2a+tan a

Answers

Answered by Ilonqueen88

4

Here is the answer:-

tan^3A-1/tanA-1

=(tanA-1)(tan^2A+1+tanA)/(tanA-1)

=tan^2A+1+tanA

=sec^2A+tanA(proved)[sec^2A-tan^2A=1]

HoPe it will help you

mktmanagerspc: thanks

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