Question

Tan³A/1+tan²A + cot³A/1+cot²A=secA cosecA- 2 sinA cos A

Answer 1

(sin^2A+cos^2A)^2=sin^4A+cos^2A+2sin^2A*cos^2A

Answer 2

$\it\huge\mathfrak\red{Answer:-}$]

=Tan³A/1+tan²A + cot³A/1+cot²A

=secA cosecA- 2 sinA cos A

=tan³A/(1+tan²A) + cot²A/(1+cot²A)

=tan³A/sec²A + cot³A/csc²A

=sin³A/cosA + cos³A/sinA

=(sin⁴A + cos⁴A)/(sinA.cosA)

=[(sin²A + cos²A)² -2(sin²A.cos²A)/(sinA.cosA)

=(1 - 2sin²A.cos²A)/(sinA.cosA)