Math, asked by virus420, 10 months ago

Tan3A×tan2A×tanA = ???

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Answered by Anonymous

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Answered by Anonymous

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SOLUTION:-

Given,

tan3A × tan2A ×tanA

L.H.S.,

tan3A = tan2A + tanA

tan3A= tan(2A+ A)

Therefore,

$tan3A = \frac{tan2A+ tanA}{1 - tan2A.tanA} \\ \\ = > tan3A - tan3A.tan2A.tanA \\ \\ = > tan2A+ tanA$

tan3A - tan2A - tanA= tan3A.tan2A.tanA

Hence,

tan3A.tan2A.tanA=tan3A - tan2A - tanA.

R.H.S

Hope it helps ☺️

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