Math, asked by suraj526, 10 months ago

tan3A.tan2A.tanA solve it?

Answers

Answered by riya43409

1

Step-by-step explanation:

tan2A can be written as tan(3A-A) now we have tan(a-b)=tana-tanb/1+tanatanb here a =2A & b=A tan2A=tan(3A-A)=tan3A-tanA/1+tan3AtanA...

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