Science, asked by Amitmandal1, 1 year ago

tan3A=tanA.tan2A.tan4A

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Answered by gvhv

can be written as tan(3A-A) now we have tan(a-b)=tana-tanb/1+tanatanbhere a =2A & b=A tan2A=tan(3A-A)=tan3A-tanA/1+tan3AtanA tan2A(1+tan3Atan2A) = tan3A-tanA tan2A + tan2Atan3AtanA = tan3A -tanA or tan2Atan3AtanA = tan3A -tanA-tan2Ahence proved

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