Math, asked by Chauhanvasu333, 3 months ago

(tan³ø-1)/(tanø-1)
= sec²ø + tanø​

Answers

Answered by gopalpvr
1

Step-by-step explanation:

LHS= (tan³ø-1)/(tanø-1)

= (tanø-1)(tan ² ø +1 + tanø) /(tanø-1)

= (tan²ø +1+tanø)

= sec²ø + tan ø (since tan²ø +1= sec²ø)

=RHS

HENCE PROVED

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