(tan³ø-1)/(tanø-1)
= sec²ø + tanø
Answers
Answered by
1
Step-by-step explanation:
LHS= (tan³ø-1)/(tanø-1)
= (tanø-1)(tan ² ø +1 + tanø) /(tanø-1)
= (tan²ø +1+tanø)
= sec²ø + tan ø (since tan²ø +1= sec²ø)
=RHS
HENCE PROVED
Similar questions