Question

tan³x/1+tan²x+cot³x/1+cot²x=1-2sin²xcos²x/sinxcox
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Answer 1

Step-by-step explanation:

your question's answer ok

Answer 2

Let us consider the LHS:

tan3 x/(1 + tan2 x) + cot3 x/(1 + cot2 x)  

On using the formula

1 + tan2x = sec2x and 1 + cot2x = cosec2x

see the attachment