Question

tan4.tan43.tan47.tan86​

Answer 1

tan4.tan43.tan47.tan86

$tan(90 - 86).tan(90 - 47).tan47tan86 \\ = cot86.cot47.tan47. tan86 \\ = cot86.cot47. \frac{1}{cot47} . \frac{1}{cot86} \\ = 1$

$\mathbb\red{hope \: it \:helps \: uhh}$

Answer 2

Answer:

Step-by-step explanation:

        ⇒tan4.tan43.tan47.tan86

         ⇒tan(90-86).tan(90-47).tan47.tan86

         ⇒cot86.cot47.tan47.tan86

      ⇒  1/tan86.1/tan47.tan47.tan86

           ⇒ 1

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