Question

(Tan45+Cot45)² + (Sin90 + Cos 0 )² + Tan60² + Cot30² + Tan420² = x​

Answer 1

sec45°=√2

cot30°=√3

sin90°=1

tan60°=√3

=√2+√3/1-√3

Answer 2

sec 45°=√2

cot 30°=√3

sin90°=1

tan60°=√3

:-√2+√3÷1-√3

hope it helps you..