Question

tan45 tan45 tan45 tan45 hshsh J's. hshsh have

Answer 1

We can rewrite the question in the picture as,
Since,
[tex] \tan(180^\circ + 45^\circ)cot(360^\circ + 45^\circ) + tan(90*8 + 45^\circ) + cot(90*7 + 45) \\ \\[/tex]
Now we know that,
$\tan and \cot$ are positive in the 3rd quadrant.
[tex]\tan(180^\circ + \theta) = \tan\theta \\ and, \cot(180^\circ + \theta) = \cot\theta[/tex]
[tex]\implies \tan45^\circ* \cot45^\circ - \tan45^\circ*\cot45^\circ \\ \because \cot(90*7 + 45) \text{ lies in the 4th quadrant and, } \\ \therefore 1 - 1 = 0 \\ \text{Hence proved!} [/tex]

Answer 2

Step-by-step explanation:

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