Math, asked by jpncs66, 12 hours ago

tan48. tan 27 tan 42 tan 67 = sec²30 - tan^2 30​

Answers

Answered by krishishah22
0

here,

LHS = tan48. tan27. tan42. tan67.

(tan48. tan42.) (tan27. tan67.)

1. 1

1

RHS = sec²30 - tan²30

1. (bcz, 1 + tan²∅ = sec²∅)

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