Question

tan48 tan23 tan 42 tan 67​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$\tan(48) \tan(23) \tan(42) \tan(67) \\ \\ \tan(90 - 42) \tan(90 - 67) \tan(42) \tan(67) \\ \\ \cot(42) \cot(67) \tan(42) \tan(67) \\ \\ \cot(42) \tan(42) \cot(67) \tan(67) \\ \\ \frac{1}{ \tan(42) } \times \tan(42) \frac{1}{ \tan(67) } \times \tan(67) \\ \\ 1 \times 1 \\ \\ 1$