Math, asked by aayra17, 1 month ago

Tan⁴A + Tan²A = Tan²A(Sec²A)

Answers

Answered by SanehaSiddique

1

Answer:

as, 1+Tan²A = sec²A

so by applying this,

R.H.S= Tan²A(1+tan²A)

= Tan²A + tan⁴A

= Tan⁴A + Tan²A = L.H.S

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