Question

tan5 tan25 tan30 tan45 tan65 tan85
plz. solve it fast

Answer 1

To find :Tan5° x tan25° x tan30° x tan45° x tan65° x tan85°

=> Tan5° x tan25° x tan30° x tan45° x tan65° x tan85°

=cot85° x cot65° x tan30° x tan45° x tan65° x tan85°    

                                                                               [tan(90-θ)=cotθ,cot(90-θ)=tanθ]

= 1 x 1 x tan30° x tan45°                                        [cotθ x tanθ=1]

=(1/√3) x 1

=1/√3

Thanks!!!

Answer 2

Answer:

Hey it's me @neyunkim..I can't unblock U there..inbox me here