tan5 tan25 tan30 tan65 tan85=?
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tan(90-85)*tan(90-65)*tan30*tan65*tan85
cot 85*cot65*tan30*tan65* tan85
(1/tan85)*(1/tan65)*tan30*tan65* tan85
tan30=1/√3
cot 85*cot65*tan30*tan65* tan85
(1/tan85)*(1/tan65)*tan30*tan65* tan85
tan30=1/√3
Answered by
2
tan(90 - x)
= sin(90 - x) ÷ cos(90 - x)
= (sin90cosx - cos90sinx) ÷ (cos90cosx + sin90sinx)
= (1cosx - 0sinx) ÷ (0cosx + 1sinx)
= (cosx) ÷ (sinx)
= cosx/sinx
= cotx
= 1/tanx
so,
tan(x) × tan(90 - x) = 1 or we can say that:
tan(A) × tan(B) = 1
where A + B = 90 degrees
and A and B are positive and does not equal to 90 nor 0
**********
5 + 85 = 90
25 + 65 = 90
tan(5) tan(25) tan(30) tan(65) tan(85)
= tan(5)tan(85) × tan(25)tan(65) × tan(30)
= 1 × 1 × tan(30)
= tan(30)
= 1/√3
where x does not equal to 0 or 90
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