Question

tan5 theta+tan3 theta/4cos4 theta(tan5 theta-tan3 theta)=?​

Answer 1

Step-by-step explanation:

brbehrh is a touch mouse with the right hand side and the other two are the SI units of the question of the question of the answer

Answer 2

Answer:

Let A = θ.

\frac{tan5A+tan3A}{tan5A-tan3A}=\frac{sin5A\ cos3A+sin3A\ cos5A}{sin5A\ cos3A-sin3A\ cos5A}\\\\=\frac{Sin(3A+5A)}{sin(5A-3A)}=\frac{sin8A}{sin2A}\\\\=\frac{2sin4A\ cos4A}{sin2A}=\frac{2*2sin2A\ cos2A\ cos4A}{sin2A}\\\\=4 cos2A\ cos4A