Question

tan50°=2tan 10°+tan40°​

Answer 1

ANSWER IS IN THE ATTACHMENT

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Answer 2

Step-by-step explanation:

take RHS ---------

tan10 + tan10 + tan 40

tan 10 + tan50(1-tan10tan40)

tan 10 + tan 50 - tan10tan40tan50

tan 10 (1-tan40tan50) + tan50

tan 10 ($\frac{tan40+tan50}{tan90\\}$) + tan 50

∵  tan90=1/0    

∴ so tan10($\frac{tan40+tan50}{tan90\\}$) + tan50=0

we will left with tan 50

thus LHS=RHS hence proved