tan50°=tan40°+2tan10°
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Step-by-step explanation:
We know that,
tan(A-B) = (tanA-tanB)/(1+tanAtanB)
Replacing A and B by 50˚ and 40˚ respectively,
→tan(50˚-40˚) = (tan50˚-tan40˚)/(1+tan50˚tan40˚)
tan10˚ = (tan50˚-tan40˚)/(1+tan50˚cot50˚) [cotx=tan(90-x)]
tan10˚ = (tan50˚-tan40˚)/(1+1)
2tan10˚ = tan50˚ - tan40˚
∴tan50˚=tan40˚+2tan10˚
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