Math, asked by trupti084, 9 months ago

tan50°=tan40°+2tan10°

Answers

Answered by adityamahale2003

21

Step-by-step explanation:

We know that,

tan(A-B) = (tanA-tanB)/(1+tanAtanB)

Replacing A and B by 50˚ and 40˚ respectively,

→tan(50˚-40˚) = (tan50˚-tan40˚)/(1+tan50˚tan40˚)

tan10˚ = (tan50˚-tan40˚)/(1+tan50˚cot50˚) [cotx=tan(90-x)]

tan10˚ = (tan50˚-tan40˚)/(1+1)

2tan10˚ = tan50˚ - tan40˚

∴tan50˚=tan40˚+2tan10˚

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