tan55°tan23°tan35°tan67°=1
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taking LHS side
tan55°tan35°tan23°tan67°
(we know that tan(90-theta)=cot theta)
tan (90-55)tan35°tan(90-23)tan67°
(cot35°tan35°)(cot67°tan67°)
1×1=1
therefore LHS=RHS
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tan55°tan35°tan23°tan67°
(we know that tan(90-theta)=cot theta)
tan (90-55)tan35°tan(90-23)tan67°
(cot35°tan35°)(cot67°tan67°)
1×1=1
therefore LHS=RHS
hope it helps you
mark me as brainlist ❤❤
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