Math, asked by jied2815, 1 year ago

Tan5degree tan25degree tan30degree tan30degree tan65degree tan85degree

Answers

Answered by vigneshandalamowz98e
0

=

Tan5*Tan25*Tan30*Tan30*Tan65*Tan85

=

Tan5*Tan85*Tan65*Tan25*Tan30*Tan30

=

Tan5*1cot85*Tan65*1cot25*Tan30* Tan30

=

Tan5*1/Tan5*Tan65*1/Tan65*Tan30* Tan30

=

1/√3*1/√3

=

1/3 is the answer

identies used are

Tan(theta)=1/cot(theta)

cot(theta)=Tan(90-theta)

Tan30=1/√3

hope u like the answer

pls mark it as brainiest

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