tan6 a+3 tan2 a.sec2 a +1 = sec6 a
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Answered by
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RHS = sec^6 a = (sec^2 a)^3
= (1+tan^2a)^3
= 1 + (tan^2 a)^3 + 3 tan^2 a (1+tan^2 a)
= 1 + tan^6 a + 3 tan^2 a * sec^2 a.
= LHS.
Hope this helps!
= (1+tan^2a)^3
= 1 + (tan^2 a)^3 + 3 tan^2 a (1+tan^2 a)
= 1 + tan^6 a + 3 tan^2 a * sec^2 a.
= LHS.
Hope this helps!
Answered by
45
hope this will help you
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