Question

tan60×cosec²45°+sec²60°×tan45°

Answer 1

Dear Student:

Tan60×cosec²45°+sec²60°×tan45°

Tan60°=√3

cosec45°=√2

sec60° = 2

tan45° =1

Tan60×cosec²45°+sec²60°×tan45°

=$\sqrt{3}*\sqrt{2} ^{2}+2^{2}*1$

=$2(\sqrt{3} +2)$

Hope it helps.

thanks

With regards