tan60×(tan170-tan140)
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may be its question answer is =1
pinaki2:
no
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tanA-tanB=tan(A-B)×(1+tanA×tanB)
=tan60×[tan(170-140)×(1+tan170tan140)]
=tan60[tan30×(1 + tan170tan140)]
=rt(3)×1/rt(3)×(1 + tan170tan140)
=1 + tan170 tan140
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