Math, asked by monimonica791, 1 year ago

tan60° cos60°+cot60°sin 60°​

Answers

Answered by ItSdHrUvSiNgH
16

Step-by-step explanation:

\huge\underline{\underline{\sf ANSWER}}\\ \tan(60)  \cos(60)  +  \cot(60)  \sin(60)  \\  \sqrt{3}  \times  \frac{1}{2}  +  \frac{1}{ \sqrt{3} }  \frac{ \sqrt{3} }{2}  \\  \frac{ \sqrt{3} }{2}  +  \frac{1}{2}  \\  \frac{ \sqrt{3 } + 1 }{2}

Answered by Anonymous
12

Step-by-step explanation:

 \tan(60)   \cos(60)  +  \cot(60)  \sin(60)  \\  \\  \sqrt{3}  \times  \frac{1}{2}  +  \frac{1}{ \sqrt{3} }  \times  \frac{ \sqrt{3} }{2}  \\  \\   \frac{ \sqrt{3} }{2}  +  \frac{1}{2}  \\  \\  \frac{ \sqrt{3 }  + 1}{2}

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