Math, asked by rasmisureshdevi, 1 year ago

(tan62/cot28)/1/1.732(tan20*tan60*tan70)

Answers

Answered by Anonymous
0
(tan 62/cot 28)/1/1.732(tan20*tan60*tan 70)=(1/1)/1/root3(1*root3)
                                                                     =1/3
Answered by Samz
3
(tan 62 / cot 28) /1/  1.732(  tan 20*tan 60 * tan 70)  =   [tan 62 / tan(90-28)] /1/root3 [tan20*tan60*cot(90-70)]  = (tan 62/ tan 62 )/1/root3(tan 20 *tan 60* cot 20)  = (1/1)/root 3(tan 60)=  1/root 3* root 3 = 1/3
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