Math, asked by dinkoo, 6 months ago

tan62°=2tan34°+tan28°​

Answers

Answered by dilliprasaddhakal528
6

=> tan 62° = tan (34° + 28°)

=> tan 62° = (tan 34° + tan 28°) / (1 - tan

34° × tan 28°)

=> tan 62° × (1 - tan34° × tan28°) =

tan34° + tan 28°

=> tan 62° - tan 34° × tan 28° × tan 62° =

tan 34° + tan 28°

=> tan 62° - tan 34° × tan 28° × tan (90° -28°) = tan 34° + tan 28°

=> tan 62° - tan 34° × tan 28° × cot 28° =

tan 34° + tan 28°

=> tan 62° - tan 34° × 1 = tan 34° + tan28°

[ since, tanA × cotA = 1]

=> tan 62° = tan 34° + tan 34° + tan 28°

=> tan 62° = 2 tan 34° + tan 28°

I hope this help you.

Similar questions