Question

tan⁶20⁰-33tan⁴20⁰+27tan²20⁰ is​

Answer 1

Answer:

Step-by-step explanation:

e know, tan60∘=3–√

⇒tan(3∗20∘)=3–√

⇒3tan20∘−tan320∘1−3tan220∘=3–√

⇒(3tan20∘−tan320∘1−3tan220∘)2=3

⇒9tan220∘+tan620∘−6tan420∘=3(1+9tan220∘−6tan220∘)

⇒9tan220∘+tan620∘−6tan420∘=3+27tan220∘−18tan220∘

⇒tan620∘−33tan420∘+27tan220∘=3