Question

(Tan63°+cot23°)/(tan27°+cot67°)

Answer 1

Answer:

Step-by-step explanation:

We know that: tan 63=cot(90-63) i.e. cot27 - eq. (1)

Also, cot23= tan( 90-23) = tan 63 -eq2

ATQ, tan 63+ cot23/tan63+cot23 =1 --(from eq1 and eq2)

Hence, the answer is 1.

Answer 2

$\frac{tan63^{\circ}+cot23^{\circ}}{tan27^{\circ}+cot67^{\circ}}=4.67$

Step-by-step explanation:

Given :$\frac{tan63^{\circ}+cot23^{\circ}}{tan27^{\circ}+cot67^{\circ}}$

Substitute the values then, we get

$\frac{1.96+2.38}{0.51+0.42}$

$\frac{4.34}{0.93}$

Using adding property of integers

Removing decimal of numerator and denominator

$\frac{\frac{434}{100}}{\frac{93}{100}}$

When from right side the decimal after two digit then we write 100 in denominator of the number and remove the decimal of that number.

$\frac{434}{100}\times \frac{100}{93}$

$4.67$

Hence, $\frac{tan63^{\circ}+cot23^{\circ}}{tan27^{\circ}+cot67^{\circ}}=4.67$

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