Math, asked by snehatrivedi16904, 10 months ago

Tan63°+cot23°/tan37°+cot27°-tan63°tan67°

Answers

Answered by Aloi99
0

Answer:

QUESTION:-

Tan63°+cot23°/tan37°+cot27°-tan63°tan67°

Step-by-step explanation:

Tan63°=Cot(90-63)°

=>Cot37°

Cot27°=Tan(90-27)

=>Tan63°

Cot37°+Cot23°/Tan37°+Cot27°-Tan63°×Tan67

Cot=1/Tan

1/Tan37°+Cot23°/Tan37°+Tan63°-Tan63°×Tan67

1+Cot23°/Tan37°+Tan63°-Tan63°×Tan67°

=>1+Cot23°/Tan37°×Tan67°

HOPE IT HELPS

Answered by Rijul63
1

Answer:

Tan63°+cot23°/tan37°+cot27°-tan63°tan67

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