Question

tan6tan26tan64tan84​

Answer 1

tan(90-84)×tan(90-64)×tan64×tan84

=cot84×cot64×tan64×tan84

=1/tan84×1/tan64×tan64×tan84

=1×1

=1

Your answer is 1....

I hope it'll help uuu...

Answer 2

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \boxed{\boxed { \huge \mathcal\red{ solution}}}}$

$\implies \: tan6 \degree \: tan26 \degree tan64 \degree \: tan84 \degree \\ \implies \: tan6 \degree \: tan84 \degree tan64 \degree \: tan26\degree \\ \implies \: tan6 \degree \: cot(90 \degree - 84 \degree) tan64 \degree \: cot( 90 \degree- 84 \degree ) \\ \implies \: (tan6 \: cot6 \degree)(tan64 \degree \: cot64 \degree) \\ \implies( \cancel{tan 6} \degree \times \frac{1}{ \cancel{tan6} \degree} )( \cancel{tan64} \degree \times \frac{1}{ \cancel{tan64} \degree)} \\ \implies \: (1)(1) \\ \implies \boxed{ \red{1}} \: \: (ans)$

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•Identify Used

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$\bf\green{\rightarrow sin \theta=cos(90\degree-\theta)}\\ \bf \green{\rightarrow tan \theta=cot(90\degree-\theta)}\\ \bf\green{ \rightarrow sec \theta=cosec(90\degree-\theta)}$

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