Question

tan7(3x²+4)
differencate with respect to x
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Answer 1

$y = {tan}^{7} (3 {x}^{2} + 4) \\ \\ \frac{dy}{dx} = 7 {tan}^{6} (3 {x}^{2} + 4) \frac{d}{dx} tan(3 {x}^{2} + 4) \\ \\ \frac{dy}{dx} = 7 {tan}^{6} (3 {x}^{2} + 4) \: {sec}^{2} (3 {x }^{2} + 4) \frac{d}{dx} (3 {x}^{2} + 4) \\ \\ \frac{dy}{dx} = 7 {tan}^{6} (3 {x}^{2} + 4) {sec}^{2} (3 {x}^{2} + 4)6x$