Math, asked by subho465, 1 year ago

tan70°⋅tan65°−tan70°−tan65°=1 prove that

Answers

Answered by MaheswariS
0

\textbf{To Prove:}

tan\,70^{\circ}\,tan\,65^{\circ}-tan\,70^{\circ}-tan\,65^{\circ}=1

\textbf{Solution:}

\text{Consider,}

tan\,135^{\circ}

tan\,135^{\circ}=tan(70^{\circ}+65^{\circ})

\text{Using the following identity}

\boxed{\bf\,tan(A+B)=\frac{tanA+tanB}{1-tanA\,tanB}}

-1=\dfrac{tan\,70^{\circ}+tan\,65^{\circ}}{1-tan\,70^{\circ}\;tan\,65^{\circ}}

-1(1-tan\,70^{\circ}\;tan\,65^{\circ})=tan\,70^{\circ}+tan\,65^{\circ}

-1+tan\,70^{\circ}\;tan\,65^{\circ}=tan\,70^{\circ}+tan\,65^{\circ}

\text{Rearranging terms we get}

tan\,70^{\circ}\;tan\,65^{\circ}-tan\,70^{\circ}-tan\,65^{\circ}=1

\therefore\bf\,tan\,70^{\circ}\;tan\,65^{\circ}-tan\,70^{\circ}-tan\,65^{\circ}=1

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