Question

tan74°-cot16°
ANSWER MY QUESTION​
with explanation

Answer 1

Step-by-step explanation:

Solution :-

Method-1:-

Given that

Tan 74° - Cot 16°

=> Tan (90°-16°) - Cot 16°

We know that

Tan (90°-A) = Cot A

=> Cot 16° - Cot 16°

=> 0

Tan 74°-Cot 16° = 0

Method-2:-

Given that

Tan 74° - Cot 16°

=> Tan 74° - Cot (90°-74°)

We know that

Cot (90°-A) = Tan A

=> Tan 74° - Tan 74°

=> 0

Tan 74°-Cot 16° = 0

Used formulae:-

→ Tan (90°-A) = Cot A

→ Cot (90°-A) = Tan A

Answer 2

Answer:

tan(θ) = cot(90 - θ)

tan(74) = cot(90 - 74)

tan(74) = cot(16)